I Have A Big Number

一道普通的模拟，只要从低位四个四个一切，切到第12个时全部压入即可，因为没有要求 载 之后再分万载，亿载之类。

参考代码

#include <iostream>
#include <vector>
#include <string>
using namespace std;

const vector<string> units = {
    "", "wan", "yi", "zhao", "jing", "gai", "zi", "rang", "gou", "jian", "zheng", "zai"
};

int main() {
    string N;
    cin >> N;
    vector<string> parts;

    int position = N.size();
    int count = 0;

    while(position > 0)
    {
        int start = max(0, position - 4);  
        int len = position - start;

        if(count < 11) {
            parts.push_back(N.substr(start, len));
        } else { 
            parts.push_back(N.substr(0, position));
            break;
        }

        position -= 4;   
        count++;
    }

    string res;

    for (int i = parts.size() - 1; i >= 0; --i) {
        if (parts[i] == "0000") continue;
        size_t j = 0;
        while (j < parts[i].size() - 1 && parts[i][j] == '0') ++j;
        res += parts[i].substr(j) + units[i];
    }

    cout << res << endl;

    return 0;
}